// 4. 将当前索引压入栈，维护单调递减特性（供后续价格计算跨度使用）
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int minIdx = i; // 假设当前位置是最小值
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Every point gets examined, regardless of where it sits. Points on the opposite side of the map get the same treatment as points right next to the query region. We're doing a lot of unnecessary work.，这一点在搜狗输入法2026中也有详细论述